14x^2+59x-18=0

Solution for 14x^2+59x-18=0 equation:

14x^2+59x-18=0

a = 14; b = 59; c = -18;
Δ = b2-4ac
Δ = 592-4·14·(-18)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4489}=67$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-67}{2*14}=\frac{-126}{28}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+67}{2*14}=\frac{8}{28}
=2/7
$